

Ripple Factor of single phase Half-Wave rectifier
When define in term of voltage, it is given by
γ = rms value of ac component/dc value of load voltage
= VL(ac)/VL(dc) = Vr(rms)/VL(dc)
In term of current, we have
γ = IL(ac)/IL(dc)
We see from above,
IL(ac) = √IL2 – IL(dc)2
γ = IL(ac)/IL(dc) = √IL2 – IL(dc)2/IL(dc) = √(IL/IL(dc))2 – 1
Now,
IL/IL(dc) = form factor Kf
γ = √Kf2–1
In this case of Half-Wave rectifies with resistive load but no filter Kf = π/2 = 1.57
γ = √1.572 -1 = 1.21
Alternatively, the value of γ could be found as under:
If we neglect fourth and higher harmonics in the load current, then as seen from above
IL(ac) = √IL12 + IL22 + IL32 +………
= √(ILM/2√2)2 + (√2ILM/3 π)2 + (√2ILM/15 π)2+ ………..
= 0.358ILM
γ = IL(ac)/IL(dc)
= 0.385 ILM/(ILM/π)
= 0.358ILM/0.318ILM
= 1.21
Related Topic
- Single-phase half-wave rectifier
- AVERAGE AND RMS VALUE OF SINGLE-PHASE HALF-WAVE RECTIFIER
- Efficiency of single-phase half-wave rectifier
- Frequency Component of Half-Wave Rectifier Voltage and Current
- Peak Inverse Voltage (PIV) of single phase half wave rectifier
- Peak current of single phase half wave rectifier
- Transformer Utilization Factor (TUF) of single phase half wave rectifier
- Advantage and Disadvantage of single-phase half-wave rectifier