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Peak current of single phase half wave rectifie

Assuming the voltage across the transformer secondary be sinusoidal of peak value VSM, instantaneous value of the voltage applied to the rectifier is given as

VS = VSM sin ωt

If the diode is assumed to have a forward resistance of RF ohms and reverse resistance equal to infinity, then the current flowing through the diode (or load resistance RL) is given as

i = IMAX sin ωt for 0 ≤ ωt ≤ π

i = 0 for π ≤ ωt ≤ 2π

Where peak value of current flowing through diode (or load resistance RL) is given as

IMAX  = VSM/(RF + RL)

 

 

 

 

Related Topic 

  1. Single-phase half-wave rectifier
  2. AVERAGE AND RMS VALUE OF SINGLE-PHASE HALF-WAVE RECTIFIER
  3. Efficiency of single-phase half-wave rectifier
  4. Frequency Component of Half-Wave Rectifier Voltage and Current
  5. Ripple Factor of single phase Half-Wave rectifier
  6. Peak Inverse Voltage (PIV) of single phase half wave rectifier
  7. Transformer Utilization Factor (TUF) of single phase half wave rectifier 
  8. Advantage and Disadvantage of single-phase half-wave rectifier

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