## Peak Current of bridge rectifier

Instantaneous value of voltage applied to the rectifier is given as

**V _{S} = V_{m} sin ωt**

If the diode is assumed to have a forward resistance of R_{F} ohms and reverse resistance equal to infinity, then current flowing through the load resistance is given as

**i _{1} = I_{m} sin ωt and i_{2} = 0** for the first half cycle

and **i _{1} = 0** and

**i**for second half cycle

_{2}= I_{m}sin ωtThe total current flowing through tha load resistance R_{L}, being the sum of currents i_{1} and i_{2}, is given as

**i = i _{1} + i_{2} = I_{m} sin ωt** for the whole cycle

Where peak value of current flowing through the load resistance R_{L} is given as

**I _{m} = V_{sm} / (R_{F} + R_{L})**

### Related Topic

**Full-wave bridge rectifier****Average and RMS Value of bridge rectifier****Efficiency of bridge rectifier****Ripple Factor of bridge rectifier****Peak Inverse Voltage (PIV) of bridge rectifier****Transformer Utilization Factor of bridge rectifier****Advantage of bridge rectifier****Disadvantage of bridge rectifier**