Circuit diagram: – A.C. voltage to be rectified is connected to the primary P_{1} P_{2} of a step-down transformer. S_{1 }and S_{2} is a secondary coil of the same transformer. S_{1} is connected to the portion p of the p-n junction diode. S_{2} is connected to the portion n through the load resistance R. Output is taken across the load resistance R.

Working:- During the positive half-cycle of the input A.C., suppose P_{1} is negative and P_{2} is positive. On account of induction, S_{1} become positive, S_{2} become negative. The p-n junction diode is forward biased. The resistance of p-n junction diode becomes low. The forward current flows in the direction from positive half-cycle to negative half-cycle through load resistance as shown in figure. Thus, we get output across-load.

During the negative half cycle of the input A.C., P_{1 }is positive and P_{2 }is negative. On account of mutual induction, S_{1 }become negative and S_{2 }is positive. The p-n junction diode is reverse biased. It offers high resistance and hence there is no flow of current and thus no output across load. The process is repeated. In the output, we have current corresponding to one half of the wave, the other half is missing.

That Is why the process is called half wave rectification. It is not of much use. The output signal is available in bursts and not continuously.

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